MySQL中vs.Count的情况

Question

I have problem with this query on MySQL.

If tried this version :

mysql>  SELECT
    COUNT(*),
    myCode,
    myState
FROM
    `tbl_2016`
WHERE
    `myCode` LIKE '%XI10-2-020012%'
GROUP BY
    `myState`;

The output is :

+----------+---------------+--------------------------------+
| COUNT(*) | myCode        | myState                        |
+----------+---------------+--------------------------------+
|        5 | XI10-2-020012 | NULL                           |
|        4 | XI10-2-020012 | ACTIVE                         |
|        1 | XI10-2-020012 | NOT ACTIVE                     |
+----------+---------------+--------------------------------+
2 rows in set

But if tried this other versione with CASE WHEN syntax :

mysql> SELECT
    myCode,
    COUNT(
        CASE
        WHEN myState IN (
            'Active'
        ) THEN
            1
        ELSE
            0
        END
    ) AS `Active`,
    COUNT(
        CASE
        WHEN myState IN (
            'Not Active'
        ) THEN
            1
        ELSE
            0
        END
    ) AS `Not Active`
FROM
    `tbl_2016`
WHERE
        `myCode` LIKE '%XI10-2-020012%'
GROUP BY
    `myState`;

The output is different than the first version :

+---------------+--------+------------+
| myCode        | Active | Not Active |
+---------------+--------+------------+
| XI10-2-020012 |      4 |          4 |
+---------------+--------+------------+
1 row in set

How to do resolve this ?

Can you help me?

Thank you in advance, my code below.

Answer 1

在第二个版本中使用SUM而不是COUNT