如何将此lambda表达式转换为方法参考

Question

How to convert this lambda expression into method reference. Here rs is a ResultSet and rowNum is int .

(rs, rowNum) -> getXYZ(rs,rowNum);

Answer 1

the method reference of (rs, rowNum) -> getXYZ(rs, rowNum) is in fact only this::getXYZ (assuming that method is in the same class and it is not static , otherwise it would be YourClass::getXYZ ).

But maybe the following will help to build other BiFunction s:

BiFunction<ResultSet, Integer, WhateverGetXYZReturnedType> yourMethodReference() {
    return (rs, rowNum) -> getXYZ(rs,rowNum); // or just: this::getXYZ
}

and use it with:

...(this::yourMethodReference)