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Node.js Q库:链承诺函数

[英]Node.js Q library: chain promise functions

First attempt at using node.js and making a controller. 首先尝试使用node.js并使其成为控制器。 I'm using knex for the queries, and Q library for promises. 我正在使用knex进行查询,并使用Q库进行promise。

I'm trying to chain the async functions that query the DB but end up with an error here: 我试图链接查询数据库的异步函数,但最终在这里出现错误:

this.getPosts().then(this.getTags).then(function() ...

If I do only this.getPosts() or only this.getTags() , it correctly fetches them. 如果我只执行this.getPosts()或仅this.getTags() ,它将正确地获取它们。

The read function is from the route. read功能来自路由。

var db = require('../db');
var Q = require("q");

class IndexController {
    constructor(page, data) {
        this.page = page;
        this.data = data;
    }

    getTags(){
        var deferred = new Q.defer();
        db('tags').select().then(function(tags){
            this.data.tags = tags;
            deferred.resolve();
        }.bind(this));
        return deferred.promise;
    }

    getPosts(){
        var deferred = new Q.defer();
        db('posts').select('*', 'posts.id as id', 'tags.name as tag')
        .innerJoin('users', 'posts.user_id', 'users.id')
        .leftJoin('post_tags', 'posts.id', 'post_tags.post_id')
        .leftJoin('tags', 'post_tags.tag_id', 'tags.id')
        .then(function(posts){
            this.data.posts = posts;
            deferred.resolve();
        }.bind(this));
        return deferred.promise;
    }

    read(res){ // <-- FROM ROUTE
        this.getPosts().then(this.getTags).then(function(){
            res.render(this.page, this.data);
        }.bind(this));
    }

    ...

}

knex is already using Promise so you don't have to use q . knex已经在使用Promise了,所以您不必使用q Just return it. 只需退货即可。

var db = require('../db');

class IndexController {
    constructor(page, data) {
        this.page = page;
        this.data = data;
    }

    getTags() {
        return knex('tags').select().then(function(tags) {
            this.data.tags = tags;
            return tags
        }
    }

    getPosts() {
        return knex('posts').select('*', 'posts.id as id', 'tags.name as tag')
            .innerJoin('users', 'posts.user_id', 'users.id')
            .leftJoin('post_tags', 'posts.id', 'post_tags.post_id')
            .leftJoin('tags', 'post_tags.tag_id', 'tags.id')
            .then(function(posts) {
                this.data.posts = posts;
                return posts
            }
    }

    read(res) { // <-- FROM ROUTE

    }

    ...

}

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