计算MySQL中两个日期（字符串格式）之间的差异

Question

My Client stores the visit time of a page in MySQL as varchar. He is taking the object of date class new date() from JS which is off the format

Fri Nov 25 2016 12:09:34 GMT+0530 (India Standard Time)

I want to calculate the time difference of 2 variables as shown above. It's used for the analytics purpose, time spent in a page like.

I already tried this:

SELECT TIMESTAMPDIFF(SECOND, 'Fri Nov 25 2016 12:09:34 GMT+0530 (India Standard Time)', 
'Fri Nov 25 2016 12:20:34 GMT+0530 (India Standard Time)')

How can I Do it?

Answer 1

You shoud really use mysql Date type. (Edit: Just saw in the comment why you're using varchar, so let's skip that ;) )

Anyway, you can try to cast your strings into dates using STR_TO_DATE() function

SELECT TIMESTAMPDIFF(
    SECOND,
    STR_TO_DATE('Fri Nov 25 2016 12:09:34 GMT+0530 (India Standard Time)', '%a %b %d %Y %T'),
    STR_TO_DATE('Fri Nov 25 2016 12:20:34 GMT+0530 (India Standard Time)', '%a %b %d %Y %T')
)

Answer 2

尝试这个 ：

SELECT TIMEDIFF('Nov 25 2016 12:09:34','Fri Nov 25 2016 12:20:34') as diff;

Answer 3

$dat1 = "Fri Nov 26 2016 12:09:34 GMT+0530";
$dat2 = "Fri Nov 25 2016 12:20:34 GMT+0530";

$diff = abs(strtotime($dat2) - strtotime($dat1));

$years = floor($diff / (365*60*60*24));
$months = floor(($diff - $years * 365*60*60*24) / (30*60*60*24));
$days = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24)/ (60*60*24));

printf("%d years, %d months, %d days\n", $years, $months, $days);