如何同时执行多个查询更新？

Question

So I have this three lines, and the problem is that only the last one is updating. What am I doing wrong? What can I do to them to update all three at the same time?

$query = "UPDATE arak SET ara = '$konyha' WHERE ID = 1";
$query = "UPDATE arak SET ara = '$kugli' WHERE ID = 2";
$query = "UPDATE arak SET ara = '$ronk' WHERE ID = 3";

Answer 1

You should execute each single query otherwise you execute only the last query assigned at $query

$query = "UPDATE arak SET ara = '$konyha' WHERE ID = 1"; 
your_execute_command() ... ;
$query = "UPDATE arak SET ara = '$kugli' WHERE ID = 2";
your_execute_command() ... ;
$query = "UPDATE arak SET ara = '$ronk' WHERE ID = 3";
your_execute_command() ... ;

or could yuo ca use a single query with a case clause

  UPDATE arak
  SET ara = case when ID = 1 then '$konyha' 
                 when ID = 2 then '$kugli'
                 when ID = 3 then '$ronk' 
            else ara
            end 

Answer 2

只需将这些查询组合在一个由终止符分隔的字符串中，然后使用：

mysqli_multi_query($connection,$query);