获取四个括号内的字符串（正则表达式）

Question

How i can write something like this:

var s = "[hello world](one two)";
var x = s.replace(REGEX, '<p>$1</p><b>$2</b>');

output:

<p>hello world</p><b>one two</b>

Answer 1

\n

\n

\n

console.log( "[hello world](one two)".replace(/\\[(.*)\\]\\((.*)\\)/, '<p>$1</p><b>$2</b>'));

\n

\n

\n

Answer 2

Use the following regex with negated character class .

 var s = "[hello world](one two)"; var x = s.replace(/\\[([^\\]]*)]\\(([^)]*)\\)/, '<p>$1</p><b>$2</b>'); console.log(x); 

Regex explanation here.

Answer 3

使用带有regex.exec（string）和this（（[。 ]）|（（。 ）））+（或类似于此的东西）的捕获组并构建theputut字符串