从 URI 获取路径抛出异常

Question

I have an Android application that i'm working on and now i'm trying to get a File from an URI (i'll use an intent to get an image from gallery and then upload it to a node.js server using Ion). Te problem is it always throws an exception. I tried debugging and got the Uri.toString(). It looks something kind of like this:

content://com.android.providers.media.documents/document/image%3A102

I know for a fact that it should look like this:

content://com.android.providers.media.documents/document/image:102

I know that the %3A is a representation of :, but why does it appear in the Uri and, how can i fix it? Finally, how can i get my file from this Uri?

Answer 1

i'm trying to get a File from an URI

A Uri is not a file. A Uri does not have to point to anything on the filesystem, let alone a place that you can access.

but why does it appear in the Uri

A Uri is an opaque handle. It can be whatever the ContentProvider wants it to be.

how can i fix it?

You don't, any more than you "fix" https://stackoverflow.com/questions/41795342/get-path-from-uri-throws-exception because you do not like eight-digit numbers starting with 4 . Just as the Stack Overflow Web server defines that URLs it uses, so does a ContentProvider define what Uri values it uses.

Finally, how can i get my file from this Uri?

Ideally, you don't. You use ContentResolver and openInputStream() to get an InputStream on the content identified by that Uri , and Ion uses that.

If Ion does not support this and can only work with a file, use the InputStream to copy the bytes to some FileOutputStream that you control (eg, in getCacheDir() ). Use that file for your upload, then delete the file when you are done.