如何解析包含特殊字符的JSON字符串？

Question

I am using hackerrank.com API for the code compilation. So when user enters code with compilation error the JSON response is like this

{
  "result": {
    "callback_url": "",
    "censored_compile_message": "",
    "codechecker_hash": "something",
    "compile_command": "/usr/lib/jvm/java-7-sun/bin/javac -encoding UTF-8  -classpath '*:/usr/share/java/json-simple-1.1.1.jar:/usr/share/java/junixsocket.jar:/usr/share/java/abacus-util-jdk7.jar' AddNumbers.java 1> compile.err 2>&1",
    "compilemessage": "AddNumbers.java:1: error: ';' expected\nimport java.util.Scanner;   class AddNumbers {    public static void main(String args[])    {       int x, y, z             Scanner in = new Scanner(System.in);       x = in.nextInt();       y = in.nextInt();      z = x + y;       System.out.println(z);    } }\n                                                                                                               ^\n1 error\n",
    "error_code": 0,
    "hash": "something",
    "loopback": null,
    "memory": null,
    "message": null,
    "response_s3_path": "something",
    "result": 255,
    "run_command": "",
    "server": "something",
    "signal": null,
    "stderr": null,
    "stdout": null,
    "time": null
  }
}

In this JSON "compilemessage" contains special escape characters like '' "" ; etc. so how to parse this string so that the characters remains as it is.

When I tried to parse with just normal

jsonobject.getString("compilemessage")

then it converts it into some random character as shown in the picture

Answer 1

使用Unicode代替“”或者代表每个特殊字符，或者你也可以使用/也代表空间字符“你可以使用/代表每个字符或者来自野兔的帮助如何在字符串数组java中定义特殊字符