有人可以帮我修复此代码（字符串）-java

Question

I try to write a old maid. After dealing cards,and sorting, i have two parts of card,one is playerDeck, one is computerDeck. now the pairs need to be removed.but i was stuck at this stage.

for example(just an example ) playerDeck: 'A♡', 'A♢', '8♡', '8♢', '8♠', 'Q♠', '2♠', '4♣', '7♢', '7♣', 'K♣', 'A♡', 'J♡', '9♣', '3♢'

computerDeck: '3♡','3♣', '10♡','10♠','10♣', '6♡', 'K♡','K♢', 'A♣', 'A♠', '4♢', '7♡','7♠'

    String q;
    String p;
    ArrayStringsTools AA=new ArrayStringsTools();//this is a class that i will use for removing item
    for(int i=0;i<playerDeck.length-1;i++){
        q=playerDeck[i];
        q=q.substring(0,1);//i try to find the first character 


        p=playerDeck[i+1];//after finding first character, i can compare them,and if they are same, then i can remove them
        p=p.substring(0,1);


        if(q==p){
            AA.removeItemByIndex(playerDeck,26,i);//this is the method that i used for removing same item,i will put this code below 
            AA.removeItemByIndex(playerDeck,26,i+1);//there are 51 cards in total,player has 26, computer has 25
        }

    }

public static int removeItemByIndex(String[] arrayOfStrings, int currentSize, int itemToRemove){//this is the method i used for removing item(first is the array of Deck, second is the size of Deck,third is the index of item to remove)

    if( arrayOfStrings == null || currentSize > arrayOfStrings.length) {
        System.out.println("ArrayStringsTools.removeItemByIndex: wrong call");
        return currentSize;
    }
    if( itemToRemove < 0 || itemToRemove >= currentSize ) {
        System.out.println("ArrayStringsTools.removeItem: item " 
            + itemToRemove + " out of bounds. Array Unchanged.");
        return currentSize;
    }

    int i;
    for( i = itemToRemove; i < currentSize-1; i++){
        arrayOfStrings[i] = arrayOfStrings[i+1];
    }
    arrayOfStrings[i]= null;
    return currentSize-1;

i think i wrote correctly, but it doesnt show any difference compared with the origin. the result should be: playerDeck: '8♠', 'Q♠', '2♠', '4♣', 'K♣', 'A♡', 'J♡', '9♣', '3♢' computerDeck:'10♣', '6♡', '4♢'

or is there another way to do this,because when a pair removed,there are two empty spaces, so... I've been struggling for a long time......

Answer 1

If you want to compare two strings,you can use 'equals',like

if(q.equals(p)){//q==p if true,they are save in the same location-this may not be what you want,and in this code it will be false forever.

}

Answer 2

To compare the 1st character, change this line

 if (q == p) {

to

 if (q.charAt(0) == p.charAt(0)) {

Notice that q == p checks to see if the q and p refer to the same string , and do not look at the contents at all. If you want to compare full strings (or any other object that is not a char, an int, or so on) by content, you should use equals : q.equals(p) returns true only if both have the same content.