[英]Convert string yyyymmddhhmmss into hh:mm:ss format in SQL
With the string DATETIME yyyymmddhhmmss
like 20160125173013
, I would like to convert this string into hh:mm:ss (17:30:13)
as a new column called "Time" in a table with sql update statement. 使用像20160125173013
这样的字符串DATETIME yyyymmddhhmmss
,我想将此字符串转换为hh:mm:ss (17:30:13)
作为带有sql update语句的表中名为“ Time”的新列。 However I am only able to convert it into 17:30 using the stuff function. 但是我只能使用stuff函数将其转换为17:30。 Is there any possible solution to convert? 有什么可能的解决方案可以转换?
In my statement 在我的陈述中
UPDATE db
SET Time =convert(time, stuff(substring(DATETIME,9,6),3,2,':'))
FROM db
WHERE Time IS NULL
Real Output= 17:13:00.0000000
实际输出= 17:13:00.0000000
But my expected output is 17:13:00
但我的预期输出是17:13:00
Thanks a lot! 非常感谢!
这是mysql
的奇迹:
SELECT time(str_to_date('20160125173013', '%Y%m%d%H%i%s'));
If you ar eusing SQL server then use Convert function 如果您正在使用SQL Server,请使用Convert函数
Declare @VarCharDate varchar(max)
Declare @VarCharDate1 varchar(max)
--Declare - 宣布
set @VarCharDate = '20160125173013' --- YYYYMMDDHHMMSS
--Convert - 兑换
set @VarCharDate1 =(select SUBSTRING(@VarCharDate,0,5) + '/' +
SUBSTRING(@VarCharDate,5,2) + '/' + SUBSTRING(@VarCharDate,7,2)
+ ' ' + SUBSTRING(@VarCharDate,9,2)
+':'+SUBSTRING(@VarCharDate,11,2) +':' + RIGHT(@VarCharDate,2))
select @VarCharDate1
select Convert(varchar(8),convert(datetime, @VarCharDate1, 120),114)
Do you have an actual DATETIME
field? 您有实际的DATETIME
字段吗? If so you can use DATE_FORMAT()
: 如果是这样,您可以使用DATE_FORMAT()
:
UPDATE mytable SET my_time=DATE_FORMAT(my_date, '%H:%i:%s')
If you don't have a native DATETIME
field I hope you can convert it to one, as irregular, quirky formats cause trouble and introduce a lot of overhead when parsing to convert. 如果您没有本地DATETIME
字段,我希望您可以将其转换为一个,因为不规则,古怪的格式会带来麻烦,并且在解析转换时会带来很多开销。 STR_TO_DATE()
can do the opposite of DATE_FORMAT()
and convert from arbitrary strings to native DATE
or DATETIME
values. STR_TO_DATE()
可以执行与DATE_FORMAT()
相反的操作,并将任意字符串转换为本地DATE
或DATETIME
值。
Don't confuse STORAGE with PRESENTATION 不要将存储与演示相混淆
Declare @YourTable table (DateTime varchar(25),Time time)
Insert Into @YourTable values
('20160125173013',null)
Update @YourTable
Set Time = stuff(left(right(DateTime,6),4),3,0,':')
Select *
,FormatedTime = Format(cast(Time as datetime),'HH:mm')
From @YourTable
Returns 退货
DateTime Time FormatedTime
20160125173013 17:30:00.0000000 17:30
Based on the use of the STUFF
function I believe this is Microsoft SQL Server, and not MySql. 基于STUFF
函数的使用,我相信这是Microsoft SQL Server,而不是MySql。 Therefor, you can do something like this: 因此,您可以执行以下操作:
UPDATE db
SET [Time] = CAST(SUBSTRING([DATETIME], 9, 2) +':'+
SUBSTRING([DATETIME], 11, 2) +':'+
RIGHT([DATETIME], 2) As Time)
WHERE [Time] IS NULL
Your string is no format, SQL Server will cast implicitly 您的字符串没有格式,SQL Server将隐式转换
DECLARE @YourDateTimeString VARCHAR(100)='20160125173013';
The following query will cut the first 8 digits and cast them to DATE
, which works implicitly (unseparated format). 以下查询将剪切前8位数字并将其转换为DATE
,这将隐式工作(不分隔格式)。 The time is cut from the right side, then the two :
-signs are stuffed into the right places: 时间从右侧减少,然后将两个:
符号填充到正确的位置:
SELECT CAST(LEFT(@YourDateTimeString,8) AS DATE)
,CAST(STUFF(STUFF(RIGHT(@YourDateTimeString,6),5,0,':'),3,0,':') AS TIME);
The result 结果
2016-01-25 17:30:13.0000000
If you need this as string without the trailing .0000000
( which is a pure output format question and should be done in your presentation layer! ) you can just use LEFT()
. 如果您需要将此字符串作为字符串而没有尾随.0000000
( 这是一个纯输出格式问题,应该在表示层中完成! ),则可以使用LEFT()
。 The input of this function is string (again implicitly casted), the output is a text which looks like a time . 该函数的输入是字符串(同样是隐式转换的),输出是看起来像time的文本 。
SELECT CAST(LEFT(@YourDateTimeString,8) AS DATE)
,LEFT(CAST(STUFF(STUFF(RIGHT(@YourDateTimeString,6),5,0,':'),3,0,':') AS TIME),8);
The result 结果
2016-01-25 17:30:13
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