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如何在 Java 中验证字符串是否为 JSON?

[英]How to validate a string is JSON or not in Java?

I've already said, my question is different...question is already asked here , but i want a predefined method in java which checksgiven string is json format or not.我已经说过,我的问题是不同的...问题已经在这里,但我想要一个 java 中的预定义方法,它检查给定的字符串是否为 json 格式。

if there is no predefined method then at least tell a code which checks JSON Format or not, without using try catch block..如果没有预定义的方法,那么至少告诉一个检查 JSON 格式的代码,而不使用 try catch 块。

Thanks in advance...提前致谢...

Use JSONObject's constructor from a String从字符串中使用JSONObject 的构造函数

    try {
        JSONObject o = new JSONObject(yourString);
    } catch (JSONException e) {
        LOGGER.error("No valid json");
    }
public boolean isValidJson(String jsonStr) {
    Object json = new JSONTokener(jsonStr)).nextValue();
    if (json instanceof JSONObject || json instanceof JSONArray) {
      return true;
    } else {
      return false;
    }
}

Just pass any string in this function.只需在此函数中传递任何字符串。

import com.fasterxml.jackson.core.JsonFactory;
import com.fasterxml.jackson.core.JsonParseException;
import com.fasterxml.jackson.core.JsonParser;
import com.fasterxml.jackson.core.JsonProcessingException;
import com.fasterxml.jackson.databind.DeserializationFeature;
import com.fasterxml.jackson.databind.JsonNode;
import com.fasterxml.jackson.databind.ObjectMapper;    
/**
         * 
         * @param inputJosn
         * @return
         * @throws IOException 
         * @throws JsonParseException 
         * @throws JsonProcessingException
         */
        private static boolean isJsonValid(String inputJosn) throws JsonParseException, IOException  {
            ObjectMapper mapper = new ObjectMapper();
            mapper.enable(DeserializationFeature.FAIL_ON_READING_DUP_TREE_KEY);
            JsonFactory factory = mapper.getFactory();
            JsonParser parser = factory.createParser(inputJosn);
            JsonNode jsonObj = mapper.readTree(parser);
            System.out.println(jsonObj.toString());


            return true;
        }

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