[英]Python script recursively rename all files in folder and subfolders
Hi I have a number of different files that need to be renamed to something else. 嗨,我有许多不同的文件需要重命名为其他文件。 I got this far but I want to have it so that I can have many items to replace and their corresponding replacements rather than type each one out, run the code then retype it again. 我已经走了这么远,但我想拥有它,以便我可以替换许多项及其对应的替换项,而不必逐一键入,运行代码然后再次键入。
UPDATE* Also I need the rename to only change part of the file not the whole thing so if there was a "Cat5e_1mBend1bottom50m2mBend2top-Aqeoiu31" it would just change it to "'Cat5e50m1mBED_50m2mBE2U-Aqeoiu31" UPDATE *另外,我还需要重命名以仅更改文件的一部分而不是整个文件,因此,如果存在“ Cat5e_1mBend1bottom50m2mBend2top-Aqeoiu31”,则只需将其更改为“'Cat5e50m1mBED_50m2mBE2U-Aqeoiu31”
import os, glob
#searches for roots, directory and files
for root,dirs, files in os.walk(r"H:\My Documents\CrossTalk\\"):
for f in files:
if f == "Cat5e_1mBend1bottom50m2mBend2top":#string you want to rename
try:
os.rename('Cat5e_1mBend1bottom50m2mBend2top', 'Cat5e50m1mBED_50m2mBE2U'))
except FileNotFoundError, e:
print(str(e))
Is this wath you want? 这是你想要的吗?
import os, glob
#searches for roots, directory and files
#Path
p=r"C:\\Users\\joao.limberger\\Documents\\Nova Pasta"
# rename arquivo1.txt to arquivo33.txt and arquivo2.txt to arquivo44.txt
renames={"arquivo1.txt":"arquivo33.txt","arquivo2.txt":"arquivo44.txt"}
for root,dirs,files in os.walk(p):
for f in files:
if f in renames.keys():#string you want to rename
try:
os.rename(os.path.join(root , f), os.path.join(root , renames[f]))
print("Renaming ",f,"to",renames[f])
except FileNotFoundError as e:
print(str(e))
Check if this is wath you want!!! 检查这是否是您想要的水!
import os, glob
#searches for roots, directory and files
#Python 2.7
#Path
p=r"C:\\Users\\joao.limberger\\Documents\\Nova Pasta"
# if the substring in the key exist in filename, replace the substring
# from the value of the key
# if the key is "o1" and the value is "oPrinc1" and the filename is
# arquivo1.txt ... The filename whil be renamed to "arquivoPrinc1.txt"
renames={"o1":"oPrinc1","oldSubs":"newSubs"}
for root,dirs,files in os.walk(p):
for f in files:
for r in renames:
if r in f:
newFile = f.replace(r,renames[r],1)
try:
os.rename(os.path.join(root , f), os.path.join(root , newFile))
print "Renaming ",f,"to",newFile
except FileNotFoundError , e:
print str(e)
The first thing you'd need is a dictionary
for the replacements, then a small change in your code: 您需要的第一件事是替换dictionary
,然后在代码中进行一些小的更改:
import os, glob
name_map = {
"Cat5e_1mBend1bottom50m2mBend2top": 'Cat5e50m1mBED_50m2mBE2U'
}
#searches for roots, directory and files
for root,dirs,files in os.walk(r"H:\My Documents\CrossTalk"):
for f in files:
if f in name_map:
try:
os.rename(os.path.join(root, f), os.path.join(root, name_map[f]))
except FileNotFoundError, e:
#except FileNotFoundError as e: # python 3
print(str(e))
In the name_map, the key
(string to the left of " :
") is the name of the file in your filesystem, and the value
(string to the right of the " :
") is the name you want to use. 在name_map中, key
(“ :
”左侧的字符串)是文件系统中文件的名称, value
(“ :
”右侧的字符串)是您要使用的名称。
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.