[英]Handling relationship in model in laravel
I am learning relationships in Laravel php framework and I am trying to build this query 我正在学习Laravel php框架中的关系,我正在尝试构建此查询
SELECT * FROM users u INNER JOIN link_to_stores lts ON u.id=lts.user_id INNER JOIN stores s ON lts.store_id=s.store_id WHERE lts.privilege = 'Owner'
I built this in Model 我在模型中构建了这个
Link_to_store.php Link_to_store.php
public function store()
{
return $this->belongsTo('App\Store');
}
public function user()
{
return $this->belongsTo('App\User');
}
User.php user.php的
public function store_links()
{
return $this->hasMany('App\Link_to_store');
}
Store.php Store.php
public function user_links()
{
return $this->hasMany('App\Link_to_store');
}
I tried this query but this only joins user and link_to_store table 我尝试了这个查询,但这只加入了user和link_to_store表
$personal_stores = Auth::user()->store_links->where('privilege','=','Owner');
Now I am confused how to join store table too. 现在我也很困惑如何加入商店表。 Can anyone help with this?
有人能帮忙吗?
Schema is like this 架构是这样的
Stores Table 商店表
store_id store_name
Users Table 用户表
id name
Link_to_stores Table Link_to_stores表
id store_id user_id privilege
I suppose store_links
is actually a pivot table. 我认为
store_links
实际上是一个数据透视表。 In this case, you can use belongsToMany()
, this will automatically take care of the pivot table. 在这种情况下,您可以使用
belongsToMany()
,这将自动处理数据透视表。
To do this, in your User
model you change the store function to this: 为此,在
User
模型中将商店功能更改为:
function stores() {
return $this->belongsToMany('App\Store', 'store_links', 'user_id', 'store_id')->withPivot('privilege');
}
Because the primary key of stores
is not id
, you will have to define this in you Store model with the following line: 由于
stores
的主键不是id
,因此您必须使用以下行在Store模型中定义它:
protected $primaryKey = 'store_id';
Now to get the stores for a user, you simply call 现在,为了获得用户的商店,您只需致电
$stores = Auth::user->stores()->wherePivot('privilege', 'Owner')->get();
I am learning relationships in Laravel php framework and I am trying to build this query
我正在学习Laravel php框架中的关系,我正在尝试构建此查询
SELECT * FROM users u INNER JOIN link_to_stores lts ON u.id=lts.user_id INNER JOIN stores s ON lts.store_id=s.store_id WHERE lts.privilege = 'Owner'
You are trying to do a join here. 你在这里试图加入。 You can do a join like this:
你可以这样做一个连接:
$stores = User::join('link_to_stores as lts', 'users.id', '=', 'lts.user_id')->join('stores as s', 'lts.store_id', '=', 's.id')->where('lts.privilege', 'Owner')->get();
But like Jerodev pointed out, it seems like Many to Many relationship might make more sense in your case. 但就像杰罗德夫指出的那样,在你的情况下,似乎多对多的关系可能更有意义。 The difference is that relationship will actually execute 2 queries (1 for original model, 1 for relationship).
不同之处在于关系实际上会执行2个查询(原始模型为1,关系为1)。 It will then attach the related models to the original model (which is extremely handy).
然后它会将相关模型附加到原始模型(非常方便)。
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