我如何使这个程序与空格一起工作？ （文本到 ASCII 和 ASCII 到文本）

Question

I wrote a program that turns a text into ASCII numbers, and then it turns the ASCII numbers back into the original text. Right now it works with both lowercase letters and uppercase letters but it doesn't work with spaces. This is how my code looks right now:

message_hidden = input("Enter a message that will be hidden: ")
hidden = ""
norm_message = ""
for i in message_hidden:
    hidden = hidden + str(ord(i)-23)
print(hidden)

for i in range(0, len(hidden), 2):
    code = hidden[i] + hidden[i+1]
    norm_message = norm_message + (chr(int(code)+23))
print("The first message was: ", norm_message)

My first attempt was to rewrite the first loop like this:

for i in message_hidden:
    if i.isalpha():
        hidden = hidden + str(ord(i)-23)
    else:
        hidden = hidden + i
print(hidden)

And from here I don't know how I should write the second loop to make it work. Can anyone give me some suggestions about how I should go from here?

Answer 1

ord(' ') == 32 and 32-23 == 9 , which is single digit. You are assuming that your numerical codes are all 2 digits. If you want to keep that assumption, you need to find a different way to encrypt the space character. To do this find a 2-digit number that isn't one of the numbers obtained by a-zA-Z . Using an explicit if -- encrypt the space character to this number. When decrypting, you will also need to use an explicit if to handle this case.

Alternatively, find a different function (other that subtracting by 23), which you apply to ord(letter) -- one which gives 2 digit numbers for all ord() values that you are interested in. There are infinitely many functions which satisfy this property. Whether or not you can find one which would require less code than simply putting a band aid on the space character is another question.