如何使用嵌套属性在XSLT中设置值

Question

How am I able to set the value of a variable in XSLT?

I currently have an xml like so:

<field name="Average Bitrate" timecode="01:35:14:300" value="60.01" />
<field name="Display Aspect Ratio" value="16:9" />
<field name="GOP Structure">

I would like to create a variable called aspectratio. This variable needs to have the conditions under the node field with the attribute Display Aspect Ratio. In this case the value would then be 16:9

Here is an example of my XSLT:

<xsl:variable name="root" select="$cfg//taskReport/streamnode/info/"/>
<xsl:variable name="AspectRatio" select="$root/Field[name = 'Display Aspect Ratio']">
    <xsl:value-of select="$AspectRatio/@value"/>
</xsl:variable>

What do I need to change in order to get my desired result?

Answer 1

Given the following input:

XML

<root>
    <field name="Average Bitrate" timecode="01:35:14:300" value="60.01" />
    <field name="Display Aspect Ratio" value="16:9" />
    <field name="GOP Structure"/>
</root>

the following stylesheet:

XSLT 1.0

<xsl:stylesheet version="1.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>

<xsl:template match="/">
    <xsl:variable name="AspectRatio" select="/root/field[@name='Display Aspect Ratio']/@value" />
    <test>
        <xsl:value-of select="$AspectRatio"/>
    </test>
</xsl:template>

</xsl:stylesheet> 

will return:

<?xml version="1.0" encoding="UTF-8"?>
<test>16:9</test>

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Note that XML is case-sensitive; Field does not select field .