[英]JS : Regular expression in switch case
I try to test a specific string with a switch case and I find this code :我尝试用 switch case 测试一个特定的字符串,我发现这个代码:
let prop = "date myData";
switch (true) {
case /str/.test(prop) :
console.log("tata");
break;
case /date/.test(prop):
console.log("toto");
break;
case /enum/.test(prop) :
console.log("titi");
break
default :
console.log("Nada");
break;
}
It works but it don't resolve my problem.它有效,但不能解决我的问题。 I want to get specifically the string "date" for example.例如,我想特别获取字符串“日期”。 With nothing before and nothing after.之前一无所有,之后一无所有。
I this example, I want my console to display "Nada".在这个例子中,我希望我的控制台显示“Nada”。
I don't know how to do that with this code.我不知道如何用这段代码做到这一点。 A solution ?一个办法 ? :) :)
You need either start and end signs in the regular expression您需要正则表达式中的开始和结束符号
/^date$/
or a simple test with a string and equality或带有字符串和相等性的简单测试
prop === 'date'
or或者
switch (prop) {
case 'date':
console.log('date');
break;
}
For what you have there a switch is not your first choice - also you are just comparing strings for equality - so an easier way would be the following对于你有的东西, switch 不是你的第一选择 - 你也只是比较字符串的相等性 - 所以更简单的方法是以下
let prop = "date myData"; let strings = {str: "tata", date: "toto", enum:"titi"} let res = strings[prop] || "Nada"; console.log(res);
To test for equality to multiple strings, either stack case statements like this:要测试多个字符串是否相等,可以像这样堆栈 case 语句:
switch (true) {
case prop === "date":
case prop === "param2":
// Do something
break;
}
Or test for inclusion in a static array:或者测试是否包含在静态数组中:
switch (true) {
case ["date", "param2"].includes(prop):
// Do something
break;
}
Although switching on true
is probably not the most efficient way to do this.尽管打开true
可能不是最有效的方法。
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