错误：C ++中类型为“ float”和“ int”的二进制“ operator％”类型的无效操作数

Question

Just started programing in C++ a few weeks ago and I encountered this problem:

float a,i,b,c,d,e,f;
cin>>a;
cin>>c;
if(c%2==0)
{
    d=c;
    e=1;
}
else
{
    d=0;
    e=0;
}

for (i=2;i<=a;i++)
{
     cin>>b;
     if(b%2==0)
     {
         d=d+b;
         e=e+1;
     }
}
f=d/e;
if(e==0)
    cout<<"0";
else
    cout<<fixed<<setprecision(2)<<f;

Ideally, the program should display on the screen the number "f" representing the arithmetic average.

Answer 1

The % operator is not defined for real numbers - you want the fmod() function declared in <cmath> . See http://en.cppreference.com/w/cpp/numeric/math/fmod