[英]String to Integer Input Verification Conversion
I'm writing a class to verify my input from another class. 我正在编写一个类来验证我从另一个类中输入的内容。 Everything seems to work except that my verification won't accept the exact high range value. 一切似乎都正常,除了我的验证不会接受确切的高范围值。 I have no idea why it won't accept it as -- for example -- if the highRange is 10 and the user inputs 10, !(10>10). 我不知道为什么它不接受它-例如-如果highRange是10并且用户输入10,!(10> 10)。 If you guys could care to my code over I would appreciate it! 如果你们能照顾我的代码,我将不胜感激!
import javax.swing.JOptionPane;
public class InputVerification {
private String input;
private int lowRange;
private int highRange;
private int invalidNum;
public InputVerification(String input, int lowRange, int highRange, int invalidNum) {
this.input = input;
this.lowRange = lowRange;
this.highRange = highRange;
this.invalidNum = invalidNum;
}
public int intVerify() {
String userInput = null;
int intInput = 0;
do {
do {
try {
/**
* handles any text entered instead of numbers enter -2 if
* you don't need an invalid number
*/
userInput = JOptionPane.showInputDialog(this.input);
intInput = Integer.parseInt(userInput);
if ((intInput > highRange || intInput < lowRange) && !(userInput.matches("[a-zA-Z]+"))) {
JOptionPane.showMessageDialog(null,
"Error! Please pick a number between " + lowRange + "-" + highRange + ".");
}
} catch (NumberFormatException e) {
JOptionPane.showMessageDialog(null,
"Error! Please pick a number between " + lowRange + "-" + highRange + ".");
}
} while (!userInput.matches("^[0-9]"));
if ((intInput > highRange || intInput < lowRange)) {
/**
*
* sends an error message if the number is higher than 100 or
* lower than 1 as long as the input was not text
*
*/
JOptionPane.showMessageDialog(null,
"Error! Please pick a number between " + lowRange + "-" + highRange + ".");
}
if (invalidNum != -2 && intInput == invalidNum) {
JOptionPane.showMessageDialog(null, "Error! Please pick a number between " + lowRange + "-" + highRange
+ " that is not " + invalidNum + ".");
}
} while ((intInput > highRange || intInput < lowRange || intInput == invalidNum)
&& !(userInput.matches("[a-zA-Z]+")));
return intInput;
}
}
import javax.swing.JOptionPane;
public class InputVerification {
public static Integer parseInt( String value, int min, int max ) {
try {
final int iValue = Integer.parseInt( value );
if(( min <= iValue ) && ( iValue <= max )) {
return iValue;
}
}
catch( final Throwable t ) {/**/}
return null;
}
public static int getInteger( String message, int lowRange, int highRange ) {
Integer intValue = null;
do {
final String userInput = JOptionPane.showInputDialog( message );
intValue = parseInt( userInput, lowRange, highRange );
if( intValue == null ) {
JOptionPane.showMessageDialog(null,
"Error! Please pick a number in [" +
lowRange + ".." + highRange + "]" );
}
} while( intValue == null );
return intValue.intValue();
}
public static void main( String[] args ) {
getInteger("Hello!", 0, 10 );
}
}
while (!userInput.matches("^[0-9]"));
应该
while (!userInput.matches("^[0-9]+"));
There is an error in your if condition for checking whether the number is in range: if ((intInput > highRange || intInput < lowRange) && !(userInput.matches("[a-zA-Z]+"))) {
您的if条件是否存在错误,无法检查数字是否在范围内: if ((intInput > highRange || intInput < lowRange) && !(userInput.matches("[a-zA-Z]+"))) {
With this check, the number should be out of range and not a valid number. 进行此检查后,该数字应超出范围, 并且不是有效数字。 You should change this to OR ||
您应该将其更改为OR ||
, ie if ((intInput > highRange || intInput < lowRange) || !(userInput.matches("[a-zA-Z]+"))) {
,即if ((intInput > highRange || intInput < lowRange) || !(userInput.matches("[a-zA-Z]+"))) {
Please note that the check if the input matches your regular expression (if it is a number) is not going to be very useful, since you would get an exception when parsing it as an integer earlier on. 请注意,检查输入是否与您的正则表达式(如果是数字)匹配不是很有用,因为在更早地将其解析为整数时会出现异常。
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