NSArray和NSInteger比较

Question

NSArray *array=[[NSArray alloc] initWithObjects:@"1",@"2",@"3",@"4",@"5",@"6",@"7",@"8",@"9",@"10", nil];

NSNumber *j = @(1);

for(id i in array) {

    if ([i isEqual:j])// always executes an else..I don't know why
    {
        NSLog(@"This object is matching %@",i);
    }
    else
    {
        NSLog(@"This Object is missing %@",i);
    }
    j = @([j intValue] + 1);
}

the code always executes the else. I don't know why. I want to check the array elements whether some missing in a list or not

Answer 1

您使用@"..."将字符串放入数组中，但应使用整数：

NSArray *array=[[NSArray alloc] initWithObjects:@1,@2,@3,@4,@5,@6,@7,@8,@9,@10, nil];

Answer 2

You are comparing NSString s from your array with the NSNumber j , so the comparison always fails

One way would be to use the stringValue of j instead:

NSArray *array = @[@"1",@"2",@"3",@"4",@"5",@"6",@"7",@"8",@"9",@"10"];

NSNumber *j = @(1);

for(NSString *i in array)
{
    if ([i isEqualToString:j.stringValue])
    {
        NSLog(@"This object is matching %@",i);            
    }
    else
    {
        NSLog(@"This Object is missing %@",i);            
    }
}