PHP：在下拉列表中检索所有可能的选项，并为特定记录选择选项

Question

I am still really new to PHP, I am creating a page for updating a specific record. I have passed an ID into the URL of the page, and using the ID for getting specific data for that record.

The trouble I am having is with dropdown lists. I want to pull back all possible options for that dropdown (which comes from a different table) and I have this sorted.

$status_sql = "SELECT DISTINCT AssetStatus.AssetStatusTitle AS HardwareAssetAssetStatusTitle, HardwareAssetAssetStatusID FROM HardwareAsset INNER JOIN AssetStatus ON (AssetStatus.AssetStatusID = HardwareAsset.HardwareAssetAssetStatusID) ORDER BY HardwareAssetAssetStatusTitle ASC";
$status = sqlsrv_query($database_connection, $status_sql);
while($status_option = sqlsrv_fetch_object($status)){
    echo "<option value='$status_option->HardwareAssetAssetStatusID'>".$status_option->HardwareAssetAssetStatusTitle."</option>";
}

The issue comes when i want to have an option already selected for that record. I know to get the specific option i need the following:

$status_sql = "SELECT DISTINCT AssetStatus.AssetStatusTitle AS HardwareAssetAssetStatusTitle, HardwareAssetAssetStatusID FROM HardwareAsset INNER JOIN AssetStatus ON (AssetStatus.AssetStatusID = HardwareAsset.HardwareAssetAssetStatusID)  WHERE HardwareAssetID = '".$HardwareAssetID."'";

but how do i combine these both together? Having the selected option, selected on load by default, and all other options available when opening the dropdown.

I have spent a fair amount of time searching online, but I dont think I am searching for the right thing, as I havent really turned anything up. Any help appreciated.

Answer 1

You don't have to modify the original SELECT query and put WHERE clause in it. Simply change your while loop in the following way,

while($status_option = sqlsrv_fetch_object($status)){
    $output = "<option value='$status_option->HardwareAssetAssetStatusID'";
    if($status_option->HardwareAssetAssetStatusID == $HardwareAssetID){
        $output .= " selected='selected'";
    }
    $output .= ">".$status_option->HardwareAssetAssetStatusTitle."</option>";
    echo $output;
}