PHP-比较2个数组的值

Question

I have a question regarding compare two arrays. I already search in this forum but nothing like what I want to achieve.

$stock = array("7", "5", "3");
$request = array("3", "6", "3");

What I want to achieve is, if every value in $stock is higher than $request , then I can execute the order. But in this case, request value in position 2 is higher than stock value (6 vs 5).

My question is, how is the code in PHP to compare if there is any value in $request is higher than every value in $stock ? OR to compare if every value in $stock is higher than every value in $request ?

Example of my database

Thank you in advance.

Answer 1

Simply loop through the arrays and compare the indexes in the respective arrays. Since it's a fixed length, always, there isn't need for any complex checks or handlings. This assumes that the keys are assigned by PHP, so they all start at 0 and always increase by 1.

$stock   = array("7", "5", "3");
$request = array("3", "6", "3");
var_dump(validate_order($stock, $request)); // false

$stock   = array("7", "5", "3");
$request = array("3", "4", "3");
var_dump(validate_order($stock, $request)); // true

function validate_order($stock, $request) {
    foreach ($stock as $key=>$value) // Fixed length, loop through
        if ($value < $request[$key])
            return false; // Return false only if the stock is less than the request
    return true; // If all indexes are higher in stock than request, return true
}

Since this function returns a boolean, true/false, simply use that in an if -statement, like this

if (validate_order($stock, $request)) {
    /* Put your code here */
    /* The order is valid */
} else {
    /* Order is not valid */
}

Live demo

Answer 2

function checkOrder($stock,$request){
    for($i=0; $i < count($stock); $i++){
        if($stock[$i] < $request[$i]) return false;
    }
    return true;
}