如何在Oracle中将日期字符串转换为日期

Question

Screenshot of query executed The date string in ' Sat Oct 29 10:47:50 CDT 2016 ' has to be converted to date/timestamp format in oracle query. I need to extract only date and time from it. I tried using to to_date() but didn't work. Can one someone please help.

Error: ORA-01841: (full) year must be between -4713 and +9999, and not be 0 01841. 00000 - "(full) year must be between -4713 and +9999, and not be 0" *Cause: Illegal year entered *Action: Input year in the specified range

Answer 1

Try this one:

SELECT TO_DATE(
   REGEXP_REPLACE('Sat Oct 29 10:47:50 CDT 2016', '^\w+ (\w+ \d+ \d{2}:\d{2}:\d{2}).+(\d{4})', '\1 \2'), 
      'Mon DD HH24:MI:SS YYYY')
FROM DUAL

Data type DATE or TIMESTAMP does not support any time zone information, you have to remove this part before you can do the conversion.