[英]How to create legend d3?
I took this example from internet:It works fine except that it creates only two rects. 我从互联网上举了一个例子:除了只创建两个矩形外,它工作正常。 I also fail to see why those rectangles are created since I would expect only one.
我也看不到为什么要创建这些矩形,因为我希望只有一个。 I created this fiddle which seem not to work.
我创建了这个小提琴,似乎不起作用。 https://jsfiddle.net/q4py7wxg/ .
https://jsfiddle.net/q4py7wxg/ 。 Please help.
请帮忙。
var color = d3.scale.linear()
.range(["rgb(213,222,217)", "rgb(69,173,168)", "rgb(84,36,55)", "rgb(217,91,67)"]);
var legendText = ["0 - 1000", "1000 - 2000", "2000 - 3000", "3000 - 5000"];
var legend = d3.select("body").append("svg")
.attr("class", "legend")
.attr("width", 140)
.attr("height", 200)
.selectAll("g")
.data(color.domain().slice().reverse())
.enter()
.append("g")
.attr("transform", function(d, i) { return "translate(0," + i * 20 + ")"; });
legend.append("rect")
.attr("width", 18)
.attr("height", 18)
.style("fill", color);
legend.append("text")
.data(legendText)
.attr("x", 24)
.attr("y", 9)
.attr("dy", ".35em")
.text(function(d) { return d; });
You wonder why your code... 您想知道为什么您的代码...
Creates only two rects.
仅创建两个矩形。
This is the reason: in D3, if you don't set the domain, the default domain is: 原因是:在D3中,如果您未设置域,则默认域为:
[0, 1]
And that's why you're seeing only two rectangles. 这就是为什么您只看到两个矩形的原因。 Let's see it in this snippet, where
color.domain().slice().reverse()
is the data you're passing in your code: 让我们在此代码段中查看它,其中
color.domain().slice().reverse()
是您在代码中传递的数据:
//look Ma, no domain! var color = d3.scaleLinear(); console.log(color.domain().slice().reverse());
<script src="https://cdnjs.cloudflare.com/ajax/libs/d3/4.5.0/d3.min.js"></script>
As you can see, your data is an array with only two elements. 如您所见,您的数据是一个只有两个元素的数组。
Solution : first, change your domain: 解决方案 :首先,更改您的域:
.domain(d3.range(4))
Which is the same of: 相同的是:
.domain([0,1,2,3])
And change your data accordingly: 并相应地更改数据:
.data(d3.range(4))
PS: do not change your data without changing your domain, this will extrapolate the colours, that is, the scale will return colours that are not in the range. PS:在不更改域的情况下不要更改数据,这会推断颜色,即比例尺将返回不在此范围内的颜色。
PS2: you're using the wrong scale for the task. PS2:您为任务使用了错误的比例。 It's working (kind of), but it's a strange code to any seasoned d3 coder.
它可以工作,但对于任何经验丰富的d3编码器来说,这都是一个奇怪的代码。 Consider using scales with discrete ranges, like
scaleQuantize
, scaleQuantile
or scaleThreshold
. 考虑使用具有离散范围的标尺,例如
scaleQuantize
, scaleQuantile
或scaleThreshold
。
Here is the fiddle: https://jsfiddle.net/9oxu4xyh/ 这是小提琴: https : //jsfiddle.net/9oxu4xyh/
Your are using the wrong version of D3, try d3.scaleLinear().
您使用的D3版本不正确,请尝试
d3.scaleLinear().
instead of d3.scale.linear()
而不是
d3.scale.linear()
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