在 JS 中从这个数组中获取数据

Question

Finally i get some output out of PHP instead of just the word "array". This took me a day, AAAAHHHH.

(see here for the solution)

So this is the return value from a XMLHTTP request (to PHP), via a callback in JS. I got it with print_r in PHP.

I post a snippet of the results here. My new question:

• what is this data structure made of?

• how to get elements out of this structure, such as CourseID (in JS)?

   [0] => Parse\\ParseObject Object ( [serverData:protected] => Array ( [CourseID] => DEMO2 [EndDate] => DateTime Object ( [date] => 2017-03-31 10:26:00.000000 [timezone_type] => 2 [timezone] => Z ) [InfoTitle1] => Welcome [InfoText1] => Welcome to your course, called "sense & sales". [Admin] => Remco@Demo1 )

My PHP code is

function getGroups(){
  $query = new ParseQuery("CourseInfo");
 $query->equalTo("Admin", "Remco@Demo1");
 $results = $query->find();


// echo $results      // this lead to the string "array"
//print_r($results);  // this leads to the complicated array
//echo "<script>\r\n var phpOutput = " . json_encode($results) . ";\r\n console.log(phpOutput);\r\n</script>";
// this leads to [{},{}]; 
}

Answer 1

What you want is a JavaScript Object, so you need to use JSON.

(JSON means JavaScript Object Notation.)

PHP has a json_encode function, which will do the work for you: ( http://php.net/manual/en/function.json-encode.php )

json_encode — Returns the JSON representation of a value

Try this:

PHP:

echo "<script>\r\n var phpOutput = " . json_encode($output) . ";\r\n console.log(phpOutput);\r\n</script>";

Press F12 in your browser to open the browser's Console log window in Developer Tools to see the new JavaScript Object.

Answer 2

You may want to convert your PHP object to JSON first via json_encode() .

This will allow you to easily work with it in JavaScript like you normally would with any JavaScript object.

Answer 3

I stopped trying to work with this array/object in JS. But instead i managed it on the PHP side and sent the results to JS.

Now it is all simple. (-;