[英]Django - displaying values from a dictionary nested in a list in an html template
I have the followed class-based views in my views.py file: 我的views.py文件中有以下基于类的视图:
class HomeView(TemplateView):
template_name = 'annual_means/home.html'
site_list = AnnualMean.objects.values("site").distinct()
def get_context_data(self, **kwargs):
context = super(HomeView, self).get_context_data(**kwargs)
context['sites'] = AnnualMean.objects.values("site").distinct()
return context
At the top of my html template, just for testing this out, I have {{sites}} and it is displaying: 在我的html模板的顶部,仅出于测试目的,我有{{sites}}并且它显示:
Below, I have the following html code: 下面,我有以下html代码:
{% for value in sites %}
<li>{{value}}</li>
{% endfor %}
And it lists all the key:value pairs as shown above, eg {'site': 'Belfast Centre'}, instead of just the values. 并且它列出了上面显示的所有key:value对,例如{'site':'Belfast Centre'},而不仅仅是这些值。 I assume this is due to the dictionary in the QuerySet being nested within a list. 我认为这是由于QuerySet中的字典嵌套在列表中。 Is there a way I can return just the a dictionary or otherwise get around this problem? 有没有办法我可以只返回字典或以其他方式解决这个问题?
I think you should use this as : 我认为您应该将其用作:
{% for value in sites %}
<li>{{value.site}}</li>
{% endfor %}
It will now print the values in list 现在它将打印列表中的值
You can access a key in a dictionary using the dot notation : 您可以使用点符号来访问字典中的键 :
Dictionary lookup, attribute lookup and list-index lookups are implemented with a dot notation: 字典查找,属性查找和列表索引查找均以点表示法实现:
{{ my_dict.key }} {{ my_object.attribute }} {{ my_list.0 }}
For your code, that would be: 对于您的代码,应为:
{% for value in sites %}
<li>{{value.site}}</li>
{% endfor %}
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