如何在JavaScript中对混合的数字/字母数字数组进行排序

Question

I have a mixed array that I need to sort by number, alphabet and then by digit-

['A1', 'A10', 'A11', 'A12', 'A3A', 'A3B', 'A3', 'A4', 'B10', 'B2', 'F1', '1', '2', 'F3']

how do I sort it to be like:

['1', '2', 'A1', 'A2', 'A3', 'A3A', 'A3B', 'A4', 'A10', 'A11', 'A12', 'B2', 'B10', 'F1', 'F3']

Here is what I tried:

var reA = /[^a-zA-Z]/g;
var reN = /[^0-9]/g;
function sortAlphaNum(a, b) {
    var AInt = parseInt(a.Field, 10);
    var BInt = parseInt(b.Field, 10);

    if (isNaN(AInt) && isNaN(BInt)) {
        var aA = (a.Field).replace(reA, "");
        var bA = (b.Field).replace(reA, "");
        if (aA === bA) {
            var aN = parseInt((a.Field).replace(reN, ""), 10);
            var bN = parseInt((b.Field).replace(reN, ""), 10);
            return aN === bN ? 0 : aN > bN ? 1 : -1;
        } else {
            return aA > bA ? 1 : -1;
        }
    } else if (isNaN(AInt)) {//A is not an Int
        return 1;//to make alphanumeric sort first return -1 here
    } else if (isNaN(BInt)) {//B is not an Int
        return -1;//to make alphanumeric sort first return 1 here
    } else {
        return AInt > BInt ? 1 : -1;
    }
}

fieldselecteddata.sort(sortAlphaNum);

but that only sorts it alphabetically/numeric till combination of 1 numeric and 1 character like A1 , A2 , A10 . But if there will be values like A3A , A3B in that case it wont sort properly. Can this be done with either straight JavaScript or jQuery?

Answer 1

 var arr = ['A1', 'A10', 'A11', 'A12', 'A3A', 'A3B', 'A3', 'A4', 'B10', 'B2', 'F1', '1', '2', 'F3']; // regular expression to get the alphabetic and the number parts, if any var regex = /^([az]*)(\\d*)/i; function sortFn(a, b) { var _a = a.match(regex); var _b = b.match(regex); // if the alphabetic part of a is less than that of b => -1 if (_a[1] < _b[1]) return -1; // if the alphabetic part of a is greater than that of b => 1 if (_a[1] > _b[1]) return 1; // if the alphabetic parts are equal, check the number parts var _n = parseInt(_a[2]) - parseInt(_b[2]); if(_n == 0) // if the number parts are equal start a recursive test on the rest return sortFn(a.substr(_a[0].length), b.substr(_b[0].length)); // else, just sort using the numbers parts return _n; } console.log(arr.sort(sortFn)); 

Note: the i modifier in the regular expression ( /.../i ) means case-insensitive (looks for both lowercases and uppercases).

Answer 2

Try this functionality. it give the result which you want exactly

  var arr = ['A1', 'A10', 'A11', 'A12', 'A3A', 'A3B', 'A3', 'A4', 'B10', 'B2', 'F1', '1', '2', 'F3']; function sortFn(a, b) { var ax = [], bx = []; a.replace(/(\\d+)|(\\D+)/g, function(_, $1, $2) { ax.push([$1 || Infinity, $2 || ""]) }); b.replace(/(\\d+)|(\\D+)/g, function(_, $1, $2) { bx.push([$1 || Infinity, $2 || ""]) }); while(ax.length && bx.length) { var an = ax.shift(); var bn = bx.shift(); var nn = (an[0] - bn[0]) || an[1].localeCompare(bn[1]); if(nn) return nn; } return ax.length - bx.length; } console.log(arr.sort(sortFn)); 

Answer 3

You could sort it with splitted array by type and check for equality first and then by type.

 var array = ['A1', 'A10', 'A11', 'A12', 'A3A', 'A3B', 'A3', 'A4', 'B10', 'B2', 'F1', '1', '2', 'F3']; array.sort(function (a, b) { var isNumber = function (v) { return (+v).toString() === v; }, aa = a.match(/\\d+|\\D+/g), bb = b.match(/\\d+|\\D+/g), i = 0, l = Math.min(aa.length, bb.length); while (i < l && aa[i] === bb[i]) { i++; } if (i === l) { return aa.length - bb.length; } if (isNumber(aa[i]) && isNumber(bb[i])) { return aa[i] - bb[i]; } return aa[i].localeCompare(bb[i]); }); console.log(array); 

 .as-console-wrapper { max-height: 100% !important; top: 0; } 

Answer 4

var a=[ {
    "LIST": "14:NATURAL RESOURCES"
},
{
    "LIST": "7:DIVERSITY IN LIVING ORGANISMS"
},
{
    "LIST": "3:ATOMS AND MOLECULES"
},
{
    "LIST": "10:GRAVITATION"
},
{
    "LIST": "6:TISSUES"
}]

var c=a.sort(function(a,b){
let aa=a.LIST,bb=b.LIST;
return parseInt(aa.split(":")[0] - bb.split(":")[0])

})

console.log(c)