MYSQL上个月查询未返回前9天

Question

I am querying records from the last calendar month. As it is February, it should return all the records that were added on January this year.

My Query:

    `SELECT * FROM table_name WHERE date >= 
DATE_ADD(LAST_DAY(DATE_SUB(NOW(), INTERVAL 2 MONTH)), INTERVAL 1 
DAY) AND date <= DATE_ADD(LAST_DAY(DATE_SUB(NOW(), INTERVAL 1 
MONTH)), INTERVAL 0 DAY) AND campaign = '$campaign' ORDER BY date 
ASC`

It returns some records but skips the first 9 days. It starts showing records from 10th of the previous month. What am I missing here?

Answer 1

检查您的日期字段类型，并确保您没有将其与varchar混淆。

Answer 2

SELECT * FROM table_name WHERE date between DATE_SUB(DATE_SUB(CURRENT_DATE,INTERVAL DAYOFMONTH(CURRENT_DATE)-1 DAY),INTERVAL 1 MONTH) AND DATE_SUB(DATE_SUB(CURRENT_DATE,INTERVAL DAYOFMONTH(CURRENT_DATE)-1 DAY),INTERVAL 1 DAY) AND campaign = '$campaign' ORDER BY date ASC

Answer 3

Try To Get Data in step by step like,

First, you should try below query.

SELECT Date, DATE_ADD(LAST_DAY(DATE_SUB(NOW(), INTERVAL 2 MONTH)), INTERVAL 1 DAY) AS StartDate, DATE_ADD(LAST_DAY(DATE_SUB(NOW(), INTERVAL 1 MONTH)), INTERVAL 0 DAY)  AS EndDate FROM MyTable

Second, If First Step give right date then get your data by directly writing your date rather than DATE_ADD function in where clause.

Third, If These will Give you write DATA then try to fetch data using DATE_ADD function.

Replay If you will get solution.

Answer 4

SELECT * FROM table_name其中（MONTH（date）=（MONTH（NOW（））-1）AND YEAR（date）= YEAR（NOW（）））或（MONTH（date）= 12 AND MONTH（NOW（））= 1 AND YEAR（date）=（YEAR（NOW（））-1）AND campaign ='$ campaign'ORDER BY date ASC`