相同连续数的正则表达式

Question

How do i write a regex to handle all instances where a the substring is 6 or more consecutive numbers such as this?

000000
111111
222222
333333
444444
555555

I tried [0-9]{6,} .

I plan to negative this afterwards so I can nullify strings with these cases.

Thanks in advance!

Answer 1

To match strings only consisting of 6 or more identical digits, you may use

^([0-9])\1{5,}$

The pattern matches:

• ^ - start of string
• ([0-9]) - Capturing group 1 matching a digit
• \\1{5,} - 5 or more occurrences (due to the limiting quantifier {5,} ) of the value captured into Group 1 (where \\1 is a backreference to Group 1 value)
• $ - end of string.