Ajax成功函数中的动态PHP内容

Question

I am trying to create dynamic php content on ajax success like the one below. I keep getting parse error. Not able to figure out the issue. New to PHP n Ajax

$.ajax({
    type: "GET",
    url: "edit_listing.php",
    data: {value:val},
    dataType: "JSON",
    success: function(data) { 
        txt="<php echo '<div></div>';"+
            "echo '<p></p>'; ?>";
        $("#someid").append(txt);
    }
});

Answer 1

Try this:

txt = '<div></div> <p></p>';
$("#someid").append(txt);

Explanation: You can create html and show it on page by using JS or JQuery only. There is no requirement of PHP in that.

Answer 2

As an alternative you can do it with json_encode . For example:

// php code
<?php $txt = "<div>{$somevar}</div><p>{$anothervar}</p>"; ?>

$.ajax({
    type: "GET",
    url: "edit_listing.php",
    data: {value:val},
    dataType: "JSON",
    success: function(data) {
        // php code 
        txt=<?php echo json_encode($txt); >;
        $("#someid").append(txt);
    }
});