是否有一个正则表达式会忽略被引号包围的单词

Question

I am trying to create a regular expression that will not match words in quotes but will match words without quotes eg

-"Welcome" - false
-Welcome - true

Answer 1

You could match only those words that are followed by an even number of double quotes, which means they themselves are not within quotes (assuming your quotes are always paired):

\w+(?=[^"]*("[^"]*"[^"]*)*$)

 function getWord(txt) { txt = txt.match(/\\w+(?=[^"]*("[^"]*"[^"]*)*$)/); return txt && txt[0]; } var input = document.querySelector('input'); var output = document.querySelector('span'); input.oninput = function () { output.textContent = getWord(input.value); } input.oninput();

 Word: <input value='"two" words'><br> First non-quoted: <span></span>

Answer 2

(?=([^"]*"[^"]*")*[^"]*$) will exclude all double quotes in the string and all text within those double quotes.
This will also remove all newline characters if you have any
Here is my source