如何打印字符串的偶数索引和奇数索引字符？

Question

Task at hand:

Given a string, S, of length N that is indexed from 0 to N-1, print its even-indexed and odd-indexed characters as 2 space-separated strings on a single line.

The test cases are written such that The first line contains an integer, N (the number of test cases). Each line i of the N subsequent lines contain a String.

Here is my code:

N = int(raw_input())

for i in range(0,N):
    string = raw_input()

evenlist = []
oddlist = []

for item, char in enumerate(strg):
    if item % 2 == 0:
        evenlist.append(char)
    else:
        oddlist.append(char)

print ''.join(evenlist), ''.join(oddlist)

Sample run:

The first input is:
2
Hacker
Rank

Expected output is:
Hce akr
Rn ak

But I get:

HceRn akrak

Here is a link to the assignment that might explain the question better.

Answer 1

Simpler way to achieve this is via using string slicing :

>>> my_str = 'Hacker'
>>> '{} {}'.format(my_str[::2], my_str[1::2])
'Hce akr'

Hence, your entire code could be written as:

for _ in range(int(raw_input())):
    my_str = raw_input()
    print '{} {}'.format(my_str[::2], my_str[1::2])

Answer 2

You can do, also, something like this:

inp = raw_input("Enter your input: ")

final = "{}  {}".format("".join(inp[k] for k in range(len(inp)) if k % 2 == 0), "".join(inp[k] for k in range(len(inp)) if k % 2 != 0))

Answer 3

In Python-3

for i in range(int(input())):
    STDIN = input()
    print(f"{STDIN[::2]} {STDIN[1::2]}")

input:

 2
 Hacker
 Rank

Output:

Hce akr Rn ak

Answer 4

Try the below code:

N = int(input())

evenlist = [] oddlist = []

for i in range(0,N): 
   string=input() 
   evenlist.clear() 
   oddlist.clear() 
   for item, char in enumerate(string): 
     if item % 2 == 0: 
       evenlist.append(char) 
     else: oddlist.append(char) 
   print(''.join(evenlist),''.join(oddlist))

print('')

Answer 5

The solution to the Hacker Rank problem is using string slicing and list.

n= int(input())
r = []
if(n>=1 and n<= 10):
    for i in range(n):
        r.append(input())
for s in r:
    print("{} {}".format(s[::2],s[1::2]))

Answer 6

num = int(input())
mylist = []

for words in range (num):
    words = input()
    mylist.append(words)
#print(mylist)

i=0
#Considering 0th position as even place here.
while i<len(mylist):
    print("Letters at even places = {} Letters at odd places ={}".
      format(mylist[i][0:len(mylist[i]):2], mylist[i][1:len(mylist[i]):2]))
    i+=1

This is a python solution for your question.

Answer 7

t=int(input("enter number "))
for i in range(1,t+1) :
    s=input("String")
    even=[]
    odd=[]
    for j,char in enumerate(s) :
        if j%2==0:
            even.append(char)
        else:
            odd.append(char)
   print(''.join(even), ''.join(odd))

Answer 8

t = int(input())
for i in range(t):
    s = input()
    idx = 0
    newstr = ''
    newstr2 = ''
    for letter in s:
        if idx % 2 == 0:
            newstr = newstr + s[idx]
        else:
            newstr2 = newstr2 + s[idx]
        idx += 1
    print(newstr, newstr2)

Answer 9

i=0
for t in range(int(input())):
    S = input()
    y = len(S)

    print(S[i:y+1:2],S[i+1:y+1:2] )


#output= "satisfies all the test cases of HackerRank...."

Answer 10

#using for loop and conditional statement

text=input()
for items in range(len(text)):
    if items%2==0:
        print(text[items],end='')
print(end='  ')
for items in range(len(text)):
    if items%2!=0:
        print(text[items],end='')

Answer 11

N = int(input())
for _ in range(0,N):
    my_str = input()
    print ('{} {}'.format(my_str[::2], my_str[1::2]))

#use this , this will perfectly work for this

Answer 12

I'm a new bee in coding but this is working well with all test cases solved.

T=int(input())
for i in range(T):
  S=input("")
  for item in range(length(S)):
     if item%2==0:
       print(S[item],end="")
  print(end=" ")
  for item in range(length(S)):
     if item%2!=0:
       print(S[item],end="")
  print(end='\n')

Answer 13

This also can do by just concatenating the words

Num_set = int(input())


for item in range(Num_set):
    word = input()
    new = ""
    second = ""
    for i in range(len(word)):
    
        if i%2 == 0:
            new = new + word[i] 
        else:
            second = second +word[i]
    print(new +" "+second)

Answer 14

import java.io.*;
import java.util.*;

public class Solution {


        private static void f(String s) {
            // TODO Auto-generated method stub
            char c[]=s.toCharArray();
            int i,j;

           for (i = 0; i <c.length;i++)
           { 
               System.out.print(c[i]);
                   i+=1;
                  // System.out.print(" ");
           }
           System.out.print(" ");

           for (j = 1; j<c.length;j++)
           {
               System.out.print(c[j]);
               j+=1;    
           }

        }

       public static void main(String[] args)
        {
            // TODO Auto-generated method stub
           Scanner sc=new Scanner(System.in);
           int s=sc.nextInt();
           String s1=sc.next();
           f(s1);

            String s2=sc.next();
           System.out.println();
           f(s2);
        }
}

Answer 15

Try the below algorithm. It is in Java. However the basic procedure is to 
scan the input word string along its length in increments of 2. The even 
index characters are printed first using a for loop starting with i = 0 and 
by adding an additional i++ inside the loop. The odd 
characters are printed starting the for loop from 1 and incrementing by steps 
of 2.  

import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;
import java.util.Arrays;

public class Solution {

public static void main(String[] args) {
    

    Scanner scanner = new Scanner(System.in);
    int n = scanner.nextInt();
   
    for(int iter= 1;iter<=n;iter++)
    {
        scanner.skip("(\r\n|[\n\r\u2028\u2029\u0085])?");
        String myString = scanner.nextLine();
        char[] myCharArray = myString.toCharArray();
        int t = myString.length();
                       
            for(int i = 0; i < t; i++)
                {
                    // Print each sequential character on the same line
                    System.out.print(myCharArray[i]); 
                    i++;
                }

            System.out.print(" "); 

            for(int k = 1; k < t; k++)
                {
                    // Print each sequential character on the same line
                    System.out.print(myCharArray[k]);
                    k++; 
                }
     
        System.out.print("\n");
    
        }

    }
}

Answer 16

import java.io.*;
import java.util.*;

public class Solution {

    public static void main(String[] args) {
        /* Enter your code here. Read input from STDIN. Print output to STDOUT. Your class should be named Solution. */
        Scanner s=new Scanner(System.in);
        String str;
        int T=s.nextInt();
        for(int i=0;i<T;i++){
            str=s.next();
          char c[]=str.toCharArray();
          int j,k;
          for(j=0;j<c.length;j++){
              System.out.print(c[j]);
              j+=1;
          }
          System.out.print(" ");
          for(k=1;k<c.length;k++){
              System.out.print(c[k]);
                k+=1;
          }
          System.out.println();
          }

        s.close();
    }
}

Answer 17

//In java just to update the above answer for multiple strings they have not added for // loop

import java.io.*;
import java.util.*;

public class dummy {


    public static void main(String[] args) {
         Scanner sc=new Scanner(System.in);
         System.out.print("Enter the number of test cases :");

         int s=sc.nextInt();

         //for loop for multiple strings as per the input
         for(int m=1;m<= s;m++)
         {
              System.out.print("\n Enter the string : ");       
              String s1=sc.next();
              f(s1); 
              System.out.print();       

         }

    }

    private static void f(String s1){

            char c[]=s1.toCharArray();
            int i,j;

           for (i = 0; i <c.length;i++)
           { 
               System.out.print(c[i]);
                   i+=1;
           }
           System.out.print(" ");

           for (j = 1; j<c.length;j++)
           {
               System.out.print(c[j]);
               j+=1;    
           }
        }

}