使用正则表达式排除字符串？

Question

I have some emails

info@gmail.com
epd@omi.ru
salesall@finteca.ru

I need to ignore strings that contain info, sales , so I used pattern:

'/(?!spb)[a-zA-Z0-9-_\.]+@[a-z0-9\.]+$'

But it returns [] . What am I doing wrong?

Answer 1

https://regex101.com/r/505NB9/1看起来不需要前两个字符。

Answer 2

See my working example below.

• For your code to work properly you will need to include ^ to indicate the start of a line as well.
• The reason you got [] is probably because you didn't use the re.MULTILINE option. The re.MULTILINE flag tells python to make the '^' and '$' special characters match the start or end of any line within a string, as opposed to the start or end of the entire string.

import re

test = 'info@gmail.com\nepd@omi.ru\nsalesall@finteca.ru'
print(test)

info@gmail.com
epd@omi.ru
salesall@finteca.ru

pattern = re.compile('^(?!info|sales)[[a-zA-Z0-9-_.]+@[a-z0-9.]+$', re.MULTILINE)
emails = re.findall(pattern, test)
print(emails)

['epd@omi.ru']

Answer 3

Perhaps more understandable and maintainable:

import re

string = """
info@gmail.com
epd@omi.ru
salesall@finteca.ru

some other text here with emails email@email.com included"""

rx = re.compile(r'\S+@\S+')

def ignore(value):
  lst = ['info', 'sales']
  for i in lst:
    if i in value:
      return False
  return True

emails = filter(ignore, rx.findall(string))
print(emails)
# ['epd@omi.ru', 'email@email.com']

Simply adjust the lst of ignore() as needed.