jQuery单击隐藏的元素

Question

I have

<table width="60" height="60" cellpadding="0" 
cellspacing="0" border="0" style="float: left; margin: 1px" 
background="images/data/source_red.gif">
   <tbody>
      <tr>
         <td act1="7" act3="8" store="true" art_id="4949" cnt="1" div_id="AA_4949" 
         onmouseover="artifactAlt(this,event,2)" 
         onmouseout="artifactAlt(this,event,0)" 
         valign="bottom" 
         style="background-image: url(&quot;images/d.gif&quot;); cursor: pointer;">&nbsp;</td>
      </tr>
   </tbody>
</table>

I want to make click on the element that rises when onmouseover="artifactAlt(this,event,2)" is firing, how to do that?

When I am doing $('#body').contents().find('td[art_id="4949"]')[0].click();

i get undefined and nothin happens.

Answer 1

You should use .click() method.

function artifactAlt(obj,event,number){
     $(obj).click();
}

 function artifactAlt(obj,event,number){ $(obj).click(); } $('tr').click(function(){ alert('tr clicked'); }); 

 <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <table width="60" height="60" cellpadding="0" cellspacing="0" border="0" style="float: left; margin: 1px" background="images/data/source_red.gif"> <tbody> <tr> <td act1="7" act3="8" store="true" art_id="4949" cnt="1" div_id="AA_4949" onmouseover="artifactAlt(this,event,2)" onmouseout="artifactAlt(this,event,0)" valign="bottom" style="background-image: url(&quot;images/d.gif&quot;); cursor: pointer;">abcd</td> </tr> </tbody> </table> 

Answer 2

You should try jquery trigger 's as follows

 function artifactAlt(element, event, number) { $(element).trigger('click'); } 

Usage of trigger('click') will save you one function call as jQuery internally calls trigger for a $().click() function call as pointed out in this post.