[英]Python - Comparing list of lists
I have a list with 3 lists and 3 other lists with 3 lists inside.我有一个包含 3 个列表的列表和 3 个其他列表,其中包含 3 个列表。
I want to compare the first index of list A with the first indexes of the first list B ...我想将列表 A 的第一个索引与第一个列表 B 的第一个索引进行比较...
Comparing the 22 with the 2,6,3 ... the 3 with the 4,4,66比较 22 与 2,6,3 ... 3 与 4,4,66
Can help me ?可以帮我 ?
a = [[22,3,3], [5,3,7],[1,6,3]]
b = [[2,4,7], [6,4,8],[3,66,13]] , [[2,23,6], [5,13,7],[11,6,34]] , [[22,53,6], [54,3,7],[11,6,33]]
You can try this out:你可以试试这个:
a = [[22,3,3], [5,3,7],[1,6,3]]
b = [[2,4,7], [6,4,8],[3,66,13]] , [[2,23,6], [5,13,7],[11,6,34]] , [[22,53,6], [54,3,7],[11,6,33]]
for i in range(len(a)):
for j in range(len(a[i])):
for x in range(len(b)):
for y in range(len(b[x])):
for z in range(len(b[y])):
if (a[i][j]==b[x][y][z]):
print('true')
else:
print('false')
As it prints true or false it is going to give you a long output.当它打印 true 或 false 时,它会给你一个很长的输出。 You can modify it as per your needs, and it compares properly as you mentioned in your question.
您可以根据自己的需要对其进行修改,并且如您在问题中提到的那样进行正确比较。
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