web2py URL重写

Question

I am playing with web2py url rewrite. The name of application is py2manager and I want to make it default in web2py via code:

# vim py2manager/routes.py:

routers = dict(
    BASE = dict(
        default_application='py2manager',
    )
)

But after web2py restart I can't access this page http://localhost:8000/user/login (which should be the same as old one http://localhost:8000/py2manager/default/user/login and old one works fine). Ever more I cant find logs for debugging that somehow.

My web2py version is 2.14.6-stable+timestamp.2016.05.09.19.18.48 cloned from git.

How to make correct rewrite with omitting py2manager/default path.

PS As doc I've used official man http://web2py.com/books/default/chapter/29/04/the-core#URL-rewrite

Answer 1

The default function is index , so the router needs more information to distinguish between a request for /index/user/login (where user and login are both args of the index function) and /user/login (where login is an arg of the user function). To do this, you must specify the list of functions in the relevant controller:

routers = dict(
    BASE = dict(
        default_application='py2manager',
    ),
    py2manager = dict(
        default_controller='default',
        default_function='index',
        functions=dict(
            default=['index', 'user', 'list', 'of', 'other', 'functions']
        )
    )
)

Also, if possible, you should use the URL() function to generate your URLs, as it will always produce the appropriate URL for a given route based on the configuration of your router.

Answer 2

The routes may need to be reloaded.

If you go to Admin. At the top right corner, next to the Change Admin Password button is a Reload Routes button.