[英]handling NA in if_else in r
I have the following dataset with three columns containing dates.我有以下包含日期的三列数据集。
library(dplyr)
set.seed(45)
df1 <- data.frame(hire_date = sample(seq(as.Date('1999/01/01'), as.Date('2000/01/01'), by="week"), 10),
t1 = sample(seq(as.Date('2000/01/01'), as.Date('2001/01/01'), by="week"), 10),
t2 = sample(seq(as.Date('2000/01/01'), as.Date('2001/01/01'), by="day"), 10))
#this value is actually unknown
df1[10,2] <- NA
hire_date t1 t2
1 1999-08-20 2000-05-13 2000-02-17
2 1999-04-23 2000-11-11 2000-04-27
3 1999-03-26 2000-04-15 2000-08-01
4 1999-05-07 2000-06-03 2000-08-29
5 1999-04-30 2000-05-27 2000-11-19
6 1999-04-09 2000-12-30 2000-01-26
7 1999-03-12 2000-12-23 2000-12-07
8 1999-06-25 2000-02-12 2000-09-26
9 1999-02-26 2000-05-06 2000-08-23
10 1999-01-01 <NA> 2000-03-18
I'd like to perform an if else statement such that df1$com is 1 if the difference between t1 OR t2 and hire_date is between [395,500]如果 t1 OR t2 和hiring_date 之间的差在 [395,500] 之间,我想执行一个 if else 语句,使 df1$com 为 1
The following if_else statement almost gets me there, but the NA mucks it up.下面的 if_else 语句几乎让我明白了,但 NA 把它搞砸了。 Any ideas?
有任何想法吗?
df1$com <- if_else((df1$t1 - df1$hire_date) >= 395 &
(df1$t1 - df1$hire_date) <= 500, 1,
if_else((df1$t2 - df1$hire_date) >= 395 &
(df1$t2 - df1$hire_date) <= 500, 1, 0))
You could use dplyr::case_when
instead of nesting the if_else
statements.您可以使用
dplyr::case_when
而不是嵌套if_else
语句。 It will give you easy control over how to treat NA
.它将让您轻松控制如何治疗
NA
。 And dplyr::between
will clean things up as well for your date comparisons.并且
dplyr::between
也会为您的日期比较进行清理。
df1 %>%
mutate(com = case_when(
is.na(t1) | is.na(t2) ~ 999, # or however you want to treat NA cases
between(t1 - hire_date, 395, 500) ~ 1,
between(t2 - hire_date, 395, 500) ~ 1,
TRUE ~ 0 # neither range is between 395 and 500
))
#> hire_date t1 t2 com
#> 1 1999-08-20 2000-05-13 2000-02-17 0
#> 2 1999-04-23 2000-11-11 2000-04-27 0
#> 3 1999-03-26 2000-04-15 2000-08-01 1
#> 4 1999-05-07 2000-06-03 2000-08-29 1
#> 5 1999-04-30 2000-05-27 2000-11-19 0
#> 6 1999-04-09 2000-12-30 2000-01-26 0
#> 7 1999-03-12 2000-12-23 2000-12-07 0
#> 8 1999-06-25 2000-02-12 2000-09-26 1
#> 9 1999-02-26 2000-05-06 2000-08-23 1
#> 10 1999-01-01 <NA> 2000-03-18 999
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.