删除上一行并将其替换为新行？

Question

My current code is the following:

for a in xrange (60, 0, -1):  
    b = "Sleeping for " + str(a) + " seconds\r"
    print b,
    sleep(1)

The only issue I have with it is that when it goes from 2 digit numbers to 1 digit numbers it prints secondss instead of seconds. How can I modify my code to properly replace the line when a goes from 2 digits to 1. Also, after the script is done printing the "Sleeping for __ seconds" lines am I able to replace that with a line that says "Sleeping for 60 seconds complete"

Answer 1

您需要删除打印行中的逗号才能查看打印输出

Answer 2

How about using string formatting?

for a in xrange (60, 0, -1):  
    print "Sleeping for %2d seconds...\r" % a, 
    sleep(1)
print "Sleeping for 60 seconds complete!"

Answer 3

you can print out an equal-length string of spaces to cover it up:

for a in xrange(60, 0, -1):
    out = "sleeping for {} seconds\r".format(a)
    sys.stdout.write(out)
    sys.stdout.flush()
    time.sleep(1)
    clear = " " * len(out)
    sys.stdout.write(clear + "\r")
print "Done"

you can also add ellipses to out to cover it up:

for a in xrange(60, 0, -1):
    out = "sleeping for {} seconds..\r".format(a)
    sys.stdout.write(out)
    sys.stdout.flush()
    time.sleep(1)
print "Done"