[英]ByteBuddy static method interception @Origin method
I have this static method intercepted correctly我正确拦截了这个静态方法
TypeDescription commandBase = TypePool.Default.ofClassPath()
.describe("poo.laboratoire1.Q2.Application").resolve();
new ByteBuddy()
.redefine(commandBase, ClassFileLocator.ForClassLoader.ofClassPath())
.method(named("obtenirTrame"))
.intercept(MethodDelegation.to(Mock.class))
.make()
.load(ClassLoader.getSystemClassLoader(),
ClassReloadingStrategy.Default.INJECTION);
but when I invoke the original method with this interceptor:但是当我用这个拦截器调用原始方法时:
public static boolean[] obtenirTrame(int i, @Origin Method origin){
...
origin.invoke(null, i);
...
}
I receive the new interceptor method in "origin" instead of the original method, resulting in an infinite recursion.我在“origin”中接收了新的拦截器方法而不是原始方法,从而导致无限递归。 Am I missing something or is this a bug ?
我错过了什么还是这是一个错误?
By calling the @Origin
method, you are invoking the same method that is currently executing.通过调用
@Origin
方法,您正在调用当前正在执行的相同方法。 Byte Buddy instruments a method foo
by changing a class: Byte Buddy 通过更改类来检测方法
foo
:
class Bar {
void foo() { /* some code */ }
}
into进入
class Bar {
void foo() { Interceptor.call( ... ); }
void foo$original() { /* some code */ }
}
You can use the @SuperMethod
annotation, if you want to get hold of the original.如果您想获取原始注释,可以使用
@SuperMethod
注释。 It is however more recommended to use the @SuperCall
or @Morph
annotations.然而,更推荐使用
@SuperCall
或@Morph
注释。
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.