[英]how to use ng-file-upload with grails 2.5.3
I am trying to use ng-file-upload to upload multiple files at the same time to my grails controller action. 我正在尝试使用ng-file-upload将多个文件同时上传到我的grails控制器操作。 However, I can't figure out how to get a hold of the files that are being uploaded to the action. 但是,我无法弄清楚如何获取正在上传到操作的文件。
Here is my JS code: 这是我的JS代码:
app.controller('MyCtrl', ['$scope', 'Upload', '$timeout', function ($scope, Upload, $timeout) {
$scope.uploadFiles = function (files) {
$scope.files = files;
if (files && files.length) {
Upload.upload({
url: 'http://localhost:8080/classifydemo/request/create',
data: {
files: files
}
}).then(function (response) {
$timeout(function () {
$scope.result = response.data;
});
}, function (response) {
if (response.status > 0) {
$scope.errorMsg = response.status + ': ' + response.data;
}
}, function (evt) {
$scope.progress =
Math.min(100, parseInt(100.0 * evt.loaded / evt.total));
});
}
};
}]);
And my grails action is below: 我的grails行动如下:
class RequestController {
def create() {
request.headerNames.each{
println it
}
println params
println request.getFile("file")
render "test"
}
}
The above code fails on request.getFile
. 上面的代码在request.getFile
失败。
Question 题
How can I get a hold of the files that are being uploaded to the controller so that I can process them in a loop. 如何保存正在上传到控制器的文件,以便我可以循环处理它们。
Since you have the possibility of multiple files you should use: 由于您可以使用多个文件:
request.fileNames.each {
MultipartFile file = request.getFile(it)
// do whatever you want with the file
}
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