在Python列表中删除具有相同条目的压缩对

Question

I have a list of zipped pairs (for example A)

A = [(0, 0), (0, 1), (0, 6), (0, 7), (1, 3), (1, 1), (2, 2)]

What's the best way in which I can remove all pairs where the first and the second entries equal each other (and create a new list)?

In the above example ( A ), the pairs that I wish to remove are (0, 0) , (1, 1) and (2, 2) . In this example, I wish the new list to look like this.

A_new = [(0, 1), (0, 6), (0, 7), (1, 3)]

Answer 1

You can use simple list comprehension with if clause that returns True for all unequal pairs that you want to keep:

>>> A = [(0, 0), (0, 1), (0, 6), (0, 7), (1, 3), (1, 1), (2, 2)]
>>> [(x, y) for x, y in A if x != y]
[(0, 1), (0, 6), (0, 7), (1, 3)]

Answer 2

使用filter ，它将判断函数作为第一个参数来告知要保留的元素，并将可迭代列表作为第二个参数， lambda定义了一个匿名函数。

A_new = filter(lambda x: x[0] != x[1], A)

Answer 3

you can do it with list comprehension :

a = [(0, 0), (0, 1), (0, 6), (0, 7), (1, 3), (1, 1), (2, 2)]
final = [k for k in a if k[0] != k[1]]

Output:

print(final)
>>> [(0, 1), (0, 6), (0, 7), (1, 3)]