[英]Reversing an integer in python is not working
def intreverse(n): #reverses an integer
x=0
d=0
while(n>0):
d=n%10
x=x*10+d
n=n/10
return x
Why is this code not giving me the reverse of an integer in python?为什么这段代码没有给我 python 中整数的反转?
If you are using Python 3, use integer division //
since /
will give you a floating point number.如果您使用的是 Python 3,请使用整数除法
//
因为/
会给您一个浮点数。
def intreverse(n):
x=0
d=0
while n > 0:
d = n % 10
x= x * 10 + d
n = n // 10
return (x)
You can even improve you code by deleting the variable d before the while loop because its value is reassigned when you enter the loop, and you can also use the augmented assignment operator //=
instead of n = n // 10
, so you could would be:您甚至可以通过在 while 循环之前删除变量 d 来改进您的代码,因为它的值在您进入循环时被重新分配,并且您还可以使用扩充赋值运算符
//=
而不是n = n // 10
,因此您可以将会:
def intreverse(n):
x = 0
while n > 0:
d = n % 10
x = x * 10 + d
n //= 10
return x
If you are worried about overflow for a specific integer size you can check if the integer is within say a 32-bit range with a simple if statement [-2^(31), 2^(31) - 1]如果您担心特定整数大小的溢出,您可以使用简单的 if 语句 [-2^(31), 2^(31) - 1] 检查整数是否在 32 位范围内
def intreverse(self, x: int) -> int:
negative = False
if x < 0:
negative = True
x = x * -1
res = 0
while x != 0:
res = (res * 10) + x % 10
x = x // 10
if (res > (2 ** 31) - 1) or (res < -(2 ** 31)):
return 0
return (res * -1) if negative else res
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