为什么函数返回布尔值？

Question

I am writing my own function which returns lower argument between two arguments.

My first solution was:

function min(a, b) {
  if (a < b)
    return a;
  else
    return b;
}

console.log(min(0, 10));
// → 0

But I wanted to simplify it and wrote another one function:

function min(a, b) {
   return a ? a < b : b;
}
console.log(min(0, 10));
// → true

Why my second function returns boolean value instead of number? Can I change this behavior?

Answer 1

It should be

function min(a, b) {
   return a < b ? a : b;
}
console.log(min(0, 10));

Answer 2

Your ternary operater is a little funky.

It should be boolean ? returnValueForTrue : returnValueForFalse; boolean ? returnValueForTrue : returnValueForFalse;

So yours is doing a ? boolean : b a ? boolean : b and I'm not sure what that actually turns into. a ? boolean a ? boolean would turn into a boolean.

So yours should be

return a < b ? a : b;