如何获取基于特定列的所有不同行？

Question

It seems due to changes in MySQL 5.7 or higher, the SQL mode ONLY_FULL_GROUP_BY is enabled by default so the good old code I had which looked like the following:

Table::where('name', 'LIKE', '%'.$search_str.'%')
    ->groupBy('name')
    ->get();

now throws the error...

SQLSTATE[42000]: Syntax error or access violation: 1055 Expression #1 of SELECT list is not in GROUP BY clause and contains nonaggregated column

I tried updating my code in various ways to try and make it work but no luck.

This is what I currently have:

Table::where('name', 'LIKE', '%'.$search_str.'%')
    ->selectRaw('name, ANY_VALUE(id), ANY_VALUE(col_a), ANY_VALUE(col_b), ANY_VALUE(col_c), ANY_VALUE(col_d)')
    ->groupBy('name')
    ->get();

This doesn't throw any errors but the column data is missing.

I've also tried:

Table::where('name', 'LIKE', '%'.$search_str.'%')
    ->groupBy('name')
    ->groupBy('id')
    ->get();

Which does not return distinct rows based on 'name'. It just returns everything.

How can I do this in Laravel Eloquent or raw MySQL?

Answer 1

The groupBy() method groups the collection's items by a given key. You should get a collection first:

Table::where('name', 'LIKE', '%'.$search_str.'%')
    ->get()
    ->groupBy('name');

Answer 2

In config/database.php file change 'strict' => true, to 'strict' => false, and try

Table::where('name', 'LIKE', '%'.$search_str.'%')
->groupBy('name')
->get();

I am not sure if you are looking for this.