正则表达式在冒号上拆分字符串

Question

I have a string String l = "name: kumar age: 22 relationship: single " it is comming from UI dynamically now i need to split the above string to

name: kumar
age: 22 
relationship: single

My code is :

Pattern ptn = Pattern.compile("([^\\s]+( ?= ?[^\\s]*)?)");
    Matcher mt = ptn.matcher(l);
    while(mt.find())
    {
        String col_dat=mt.group(0);
        if(col_dat !=null && col_dat.length()>0)
        {
            System.out.println("\t"+col_dat );
        }
    }

Any Suggestions will appreciated Thank you

Answer 1

You can use this regex:

\S+\s*:\s*\S+

Or this:

\w+\s*:\s*\w+

Demo: https://regex101.com/r/EgXlcD/6

Regex:

\\S+ - 1 or more non space characters

\\s* - 0 or more space characters

\\w+ - 0 or more \\w ie [A-Za-z0-9_] characters.