如何从 PHP 中的 URL 读取查询字符串

Question

如果 URL 是https://www.mohsin.com?main=17&street=71 ，那么获取“main”和“street”值的 PHP 代码是什么？

Answer 1

Please Try with this :

<?php
    $main = $_GET['main'];
    $street = $_GET['street'];
?>

Answer 2

Just call the following function:

function getQueryParameter($url, $param) {
    $parsedUrl = parse_url($url);
    if (array_key_exists('query', $parsedUrl)) {
        parse_str($parsedUrl['query'], $queryParameters);
        if (array_key_exists($param, $queryParameters)) {
            return $queryParameters[$param];
        }
    }
}

Example:

• $parameter = getQueryParameter('https://www.mohsin.com?main=17&street=71', 'main') will return 17 .
• $parameter = getQueryParameter('https://www.mohsin.com?main=17&street=71', 'street') will return 71 .
• $parameter = getQueryParameter('https://www.mohsin.com?main=17&street=71', 'invalid') will return null .

Answer 3

$main = $_GET['main'] will get the main variable and $street = $_GET['street'] will get the street variable. All URL parameters are loaded into the PHP $_GET super global array and the super global is an associative array.