使用libgit2获得未推送的提交
[英]Get unpushed commits with libgit2
问题描述
Is there a way to show all unpushed commits from all available branches with libgit 2. My idea was to use git_revparse(&spec, repo, "origin/master..master"); 
有没有办法用libgit 2显示所有可用分支中所有未推送的提交。我的想法是使用git_revparse（＆spec，repo，“ origin / master..master”）; but this gives me a git_revspec and I don't know how to use this to iterate over all commits. 但这给了我一个git_revspec，我不知道如何使用它来遍历所有提交。 Another problem is that this method is for a specific branch only. 另一个问题是该方法仅适用于特定分支。
1 个解决方案
解决方案1
2 已采纳 2017-02-09 18:38:23
Use the git_branch_iterator functions to get all of the local branches and git_branch_upstream to get their corresponding upstream branch. 使用git_branch_iterator函数获取所有本地分支，并使用git_branch_upstream获取其相应的上游分支。 Then use the git_revwalk functions to walk over all of the commits that are different between them. 然后使用git_revwalk函数遍历它们之间所有不同的提交。 Push the upstream with git_revwalk_push_ref and hide the local branch with git_revwalk_hide_ref . 推动上游git_revwalk_push_ref和隐藏与当地分部git_revwalk_hide_ref 。
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