使用HttpClient在同一呼叫中发送帖子和获取结果

Question

If Method A posts as follows:

public void testPostAndGet()
        {
            using (var client  = new HttpClient())
            {
                var uri = new Uri("https://localhost:44322/test");

                var pairs = new List<KeyValuePair<string, string>>
                {
                    new KeyValuePair<string, string>("email", "email@test.com")
                };

                var content = new FormUrlEncodedContent(pairs);

                var responsePost = client.PostAsync(uri, content).Result;

                if (responsePost.IsSuccessStatusCode)
                {

                }
            }
        }

To method B, which also returns a List :

public async Task<List<EventItem>> test()
        {
            List<EventItem> items = new List<EventItem>();

            NameValueCollection nvc = Request.Form;
            string email = nvc["email"];

            string test = "";

            try
            {
                items = await eventsService.GetAllEvents(graphClient, email);
            }
            catch (ServiceException se)
            {

            }

            return items;
        }

How can I access the List returned from method B from method A? ie How can I send a Post and Get in the same call to the same endpoint?

Answer 1

something like this will work:

public async Task<TResult> PostAsync<TResult, TInput>(string uriString, TInput payload = null) where TInput : class
    {
        var uri = new Uri(uriString);
        using (var client = GetHttpClient())
        {
            var jsonContent = JsonConvert.SerializeObject(payload, Formatting.Indented, new JsonSerializerSettings { ContractResolver = new CamelCasePropertyNamesContractResolver() });
            HttpResponseMessage response = await client.PostAsync(uri, new StringContent(jsonContent, Encoding.UTF8, "application/json"));
            if (response.StatusCode != HttpStatusCode.OK)
            {
                //Log.Error(response.ReasonPhrase);
                return default(TResult);
            }
            var json = await response.Content.ReadAsStringAsync();
            return JsonConvert.DeserializeObject<TResult>(json);
        }
    }