[英]i want output in sql
fromdate todate
1/5/2017 1/7/2017
1/5/2017 1/5/2017
1/5/2017 1/7/2017
1/5/2017 1/7/2017
1/5/2017 1/6/2017
by this syntax:- datediff(day,fromdate,todate)通过这种语法:- datediff(day,fromdate,todate)
I want output in this way:- 0_days 1_days 2_days我希望以这种方式输出:- 0_days 1_days 2_days
1 1 3 1 1 3
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.