找出文件分隔符或正则表达式

Question

I receive a file everyday with some data:

B024560HERR S, KARL-HEINZ          FAO031  D      F    18.07.17    01.08.17   14   LH 1162    18.07.17 10:30  12:35   FRA   FAO   FRA       1   LH 1163 01.08.17    FAO     03.01.17  1
    Frühbucher 10%
    inkl. Reiseleitung
    und Transfer ab/bis Flughafen
    *REPEATER, BITTE ZIMMERGEGENÜBER DER BAR 3ER
    UNVERBINDLICHER KUNDENWUNSCH
B024560HERR S, KARL-HEINZ          FAO031  D      F    18.07.17    01.08.17   14   LH 1162    18.07.17 10:30  12:35   FRA   FAO   FRA       1   LH 1163 01.08.17    FAO     03.01.17  1
B024560FRAU S, MARIA         FAO031  D      F    18.07.17    01.08.17   14   LH 1162    18.07.17 10:30  12:35   FRA   FAO   FRA       1   LH 1163 01.08.17    FAO     03.01.17  2

Link to this example file: https://www.dropbox.com/s/c39km8htjqq9q4t/example.txt?dl=1

I need to import it to a mysql database.

So this should be divided like this (using | as a divider):

B024560 | HERR S, KARL-HEINZ    |       FAO031  | D    |   F    | 18.07.17    |  01.08.17   | 14   | LH 1162   |  18.07.17 | 10:30  | 12:35   | FRA   | FAO   | FRA      |  1    |LH 1163  | 01.08.17   |  FAO   |   03.01.17  | 1  |
    Frühbucher 10%
    inkl. Reiseleitung
    und Transfer ab/bis Flughafen
    *REPEATER, BITTE ZIMMERGEGENÜBER DER BAR 3ER
    UNVERBINDLICHER KUNDENWUNSCH  |

B024560  | HERR S, KARL-HEINZ       |    FAO031  | D     |  F    | 18.07.17  |   01.08.17  |  14   | LH 1162   |  18.07.17  | 10:30   |12:35  |  FRA  |  FAO  |  FRA    |    1  |  LH 1163 | 01.08.17  |   FAO  |    03.01.17  | 1  |

B024560  | FRAU S, MARIA  |        FAO031  |  D   |    F   |  18.07.17   |  01.08.17   | 14   |  LH 1162  |   18.07.17  | 10:30   | 12:35  |   FRA  |  FAO   | FRA   |     1  |  LH 1163  | 01.08.17   |  FAO    |  03.01.17  | 2

The best that I have done was with this regex :

\s{2,}

So my problem is how can I find out the file delimeter ? Or is there another or better way to do this? The idea is to read this file with php and import to mysql database.

Answer 1

This will do what you want:

(?<=\w)\h{2,}(?=\w)        # horizontal spaces with word character beneath
|
(?=HERR|FRAU)              # "HERR" or "FRAU" literally
|
\h+(?=\d{2}\.\d{2}\.\d{2}) # a date
|
\h+(?=\d{2}:\d{2})         # time of date in xx:xx format

See your modified demo on regex101.com (and mind the modifiers!).

---

The whole snippet:

 <?php $text = <<<EOT B024560HERR S, KARL-HEINZ FAO031 DF 18.07.17 01.08.17 14 LH 1162 18.07.17 10:30 12:35 FRA FAO FRA 1 LH 1163 01.08.17 FAO 03.01.17 1 Frühbucher 10% inkl. Reiseleitung und Transfer ab/bis Flughafen *REPEATER, BITTE ZIMMERGEGENÜBER DER BAR 3ER UNVERBINDLICHER KUNDENWUNSCH B024560HERR S, KARL-HEINZ FAO031 DF 18.07.17 01.08.17 14 LH 1162 18.07.17 10:30 12:35 FRA FAO FRA 1 LH 1163 01.08.17 FAO 03.01.17 1 B024560FRAU S, MARIA FAO031 DF 18.07.17 01.08.17 14 LH 1162 18.07.17 10:30 12:35 FRA FAO FRA 1 LH 1163 01.08.17 FAO 03.01.17 2 EOT; $regex = '~ (?<=\\w)\\h{2,}(?=\\w) | (?=HERR|FRAU) | \\h+(?=\\d{2}\\.\\d{2}\\.\\d{2}) | \\h+(?=\\d{2}:\\d{2}) ~x'; $lines = explode("\\n", $text); foreach ($lines as $line) { $fields = preg_split($regex, $line); if (count($fields) > 1) { print_r($fields); } } ?>

See it working on ideone.com .

Answer 2

Kind of simple way.

Use (?m)^(B\\d+)((?:(?![ ]{9}).)+)[ ]+(.+) and a callback function.

Pass $1, $2, $3 to callback.

Split $3 with \\s+. $result = Join split array with |.
Return = Join $1 | $2 | + $result

 (?m)
 ^
 ( B \d+ )                     # (1)
 (                             # (2 start)
      (?:
           (?! [ ]{9} )
           .
      )+
 )                             # (2 end)
 [ ]+ 
 ( .+ )                        # (3)

Match example output

 **  Grp 1 -  ( pos 0 , len 7 ) 
B024560  
 **  Grp 2 -  ( pos 7 , len 18 ) 
HERR S, KARL-HEINZ  
 **  Grp 3 -  ( pos 35 , len 148 ) 
FAO031  D      F    18.07.17    01.08.17   14   LH 1162    18.07.17 10:30  12:35   FRA   FAO   FRA       1   LH 1163 01.08.17    FAO     03.01.17  1