使用pyparsing解析简单语法时出错

Question

I'm trying to parse a simple regex grammar with concatenation, disjunction, and kleene star. My grammar and tests look like this:

from pyparsing import Word, nums, Forward, Suppress, OneOrMore

#A grammar for a simple class of regular expressions
number = Word(nums)('number')
lparen = Suppress('(')
rparen = Suppress(')')

expression = Forward()('expression')

concatenation = expression + expression
concatenation.setResultsName('concatenation')

disjunction = lparen + OneOrMore(expression + Suppress('|')) + expression + rparen
disjunction.setResultsName('disjunction')

kleene = lparen + expression + rparen + Suppress('*')
kleene.setResultsName('kleene')

expression << number | concatenation | disjunction | kleene

#Test a simple input
tests = """
7
23
(7)*
(45)*
(1|2|3)
((2)*|3)
((0|1))*
""".splitlines()

for t in tests:
    print t
    print expression.parseString(t)
    print

However, the program fails on the very first test:

Traceback (most recent call last):
  File "main.py", line 34, in <module>
    print expression.parseString(t)
  File "/home/elliot/miniconda2/lib/python2.7/site-packages/pyparsing.py", line 1216, in parseString
    raise exc
pyparsing.ParseException: Expected W:(0123...) (at char 0), (line:1, col:1)

What's the problem here? Also, any other feedback on my grammar (ie how I could have done things better/simpler) would be appreciated as well.

Answer 1

The first test is not "7" . The first test is "" , because your tests string starts with an empty line. "" does not match a valid expression in your grammar.